Base | Representation |
---|---|
bin | 11110100010111100000001… |
… | …010101011010001111000011 |
3 | 122121122222222011220022002201 |
4 | 132202330001111122033003 |
5 | 120102031014414110113 |
6 | 1153420000324054031 |
7 | 40203624353360611 |
oct | 3642740125321703 |
9 | 577588864808081 |
10 | 134342304441283 |
11 | 39895284618a64 |
12 | 13098531b34317 |
13 | 59c656a8005a3 |
14 | 25262b8cb46b1 |
15 | 107e841b96cdd |
hex | 7a2f0155a3c3 |
134342304441283 has 2 divisors, whose sum is σ = 134342304441284. Its totient is φ = 134342304441282.
The previous prime is 134342304441281. The next prime is 134342304441311. The reversal of 134342304441283 is 382144403243431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134342304441283 - 21 = 134342304441281 is a prime.
Together with 134342304441281, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (134342304441281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67171152220641 + 67171152220642.
It is an arithmetic number, because the mean of its divisors is an integer number (67171152220642).
Almost surely, 2134342304441283 is an apocalyptic number.
134342304441283 is a deficient number, since it is larger than the sum of its proper divisors (1).
134342304441283 is an equidigital number, since it uses as much as digits as its factorization.
134342304441283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2654208, while the sum is 46.
The spelling of 134342304441283 in words is "one hundred thirty-four trillion, three hundred forty-two billion, three hundred four million, four hundred forty-one thousand, two hundred eighty-three".
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