Base | Representation |
---|---|
bin | 10011100011001010110… |
… | …000001000101010110000 |
3 | 11202102122001012210121210 |
4 | 103203022300020222300 |
5 | 134002321420144100 |
6 | 2505055221320120 |
7 | 166026324410100 |
oct | 23431260105260 |
9 | 4672561183553 |
10 | 1343431412400 |
11 | 478823011150 |
12 | 198448566040 |
13 | 998ba05062c |
14 | 4904577d200 |
15 | 24e2bcbbc50 |
hex | 138cac08ab0 |
1343431412400 has 1080 divisors, whose sum is σ = 5802109551936. Its totient is φ = 262697164800.
The previous prime is 1343431412377. The next prime is 1343431412429. The reversal of 1343431412400 is 42141343431.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 186921607 + ... + 186928793.
Almost surely, 21343431412400 is an apocalyptic number.
1343431412400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1343431412400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2901054775968).
1343431412400 is an abundant number, since it is smaller than the sum of its proper divisors (4458678139536).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1343431412400 is a wasteful number, since it uses less digits than its factorization.
1343431412400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7267 (or 7232 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 1343431412400 its reverse (42141343431), we get a palindrome (1385572755831).
The spelling of 1343431412400 in words is "one trillion, three hundred forty-three billion, four hundred thirty-one million, four hundred twelve thousand, four hundred".
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