Search a number
-
+
13434624000 = 21132537317
BaseRepresentation
bin11001000001100010…
…00001100000000000
31021200021121121111200
430200301001200000
5210003230432000
610101034341200
7653631264000
oct144061014000
937607547450
1013434624000
115774549946
12272b28a800
131361446b75
14916384000
155396a4500
hex320c41800

13434624000 has 1152 divisors, whose sum is σ = 59793552000. Its totient is φ = 2890137600.

The previous prime is 13434623999. The next prime is 13434624011. The reversal of 13434624000 is 42643431.

13434624000 is a `hidden beast` number, since 1 + 3 + 4 + 34 + 624 + 0 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (1152).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 790271992 + ... + 790272008.

It is an arithmetic number, because the mean of its divisors is an integer number (51904125).

Almost surely, 213434624000 is an apocalyptic number.

13434624000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13434624000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29896776000).

13434624000 is an abundant number, since it is smaller than the sum of its proper divisors (46358928000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13434624000 is an equidigital number, since it uses as much as digits as its factorization.

13434624000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81 (or 34 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

The spelling of 13434624000 in words is "thirteen billion, four hundred thirty-four million, six hundred twenty-four thousand".