13440100211 has 4 divisors (see below), whose sum is σ = 13479982152. Its totient is φ = 13400218272.

The previous prime is 13440100099. The next prime is 13440100273. The reversal of 13440100211 is 11200104431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11200104431 = 467 ⋅23983093.

It is a cyclic number.

It is not a de Polignac number, because 13440100211 - 2²² = 13435905907 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13440100211.

It is not an unprimeable number, because it can be changed into a prime (13440160211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19940465 + ... + 19941138.

It is an arithmetic number, because the mean of its divisors is an integer number (3369995538).

Almost surely, 2^13440100211 is an apocalyptic number.

13440100211 is a deficient number, since it is larger than the sum of its proper divisors (39881941).

13440100211 is an equidigital number, since it uses as much as digits as its factorization.

13440100211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39881940.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 13440100211 its reverse (11200104431), we get a palindrome (24640204642).

The spelling of 13440100211 in words is "thirteen billion, four hundred forty million, one hundred thousand, two hundred eleven".