13440100301 has 4 divisors (see below), whose sum is σ = 14024452512. Its totient is φ = 12855748092.

The previous prime is 13440100279. The next prime is 13440100351. The reversal of 13440100301 is 10300104431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13440100301 is a prime.

It is a super-2 number, since 2×13440100301² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13440100301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13440100351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 292176071 + ... + 292176116.

It is an arithmetic number, because the mean of its divisors is an integer number (3506113128).

Almost surely, 2^13440100301 is an apocalyptic number.

It is an amenable number.

13440100301 is a deficient number, since it is larger than the sum of its proper divisors (584352211).

13440100301 is an equidigital number, since it uses as much as digits as its factorization.

13440100301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 584352210.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13440100301 its reverse (10300104431), we get a palindrome (23740204732).

The spelling of 13440100301 in words is "thirteen billion, four hundred forty million, one hundred thousand, three hundred one".