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1344011225542 = 22836761351217
BaseRepresentation
bin10011100011101101010…
…011111100100111000110
311202111010110020100201121
4103203231103330213012
5134010013333204132
62505232532544154
7166046564631316
oct23435523744706
94674113210647
101344011225542
11478aa0331367
1219858a78205a
13999801cba2b
144909c78d446
1524e62b4d497
hex138ed4fc9c6

1344011225542 has 16 divisors (see below), whose sum is σ = 2023445570832. Its totient is φ = 669530085120.

The previous prime is 1344011225539. The next prime is 1344011225551. The reversal of 1344011225542 is 2455221104431.

It is a junction number, because it is equal to n+sod(n) for n = 1344011225498 and 1344011225507.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3651118 + ... + 4002334.

It is an arithmetic number, because the mean of its divisors is an integer number (126465348177).

Almost surely, 21344011225542 is an apocalyptic number.

1344011225542 is a deficient number, since it is larger than the sum of its proper divisors (679434345290).

1344011225542 is a wasteful number, since it uses less digits than its factorization.

1344011225542 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 358263.

The product of its (nonzero) digits is 38400, while the sum is 34.

Adding to 1344011225542 its reverse (2455221104431), we get a palindrome (3799232329973).

The spelling of 1344011225542 in words is "one trillion, three hundred forty-four billion, eleven million, two hundred twenty-five thousand, five hundred forty-two".

Divisors: 1 2 283 566 6761 13522 351217 702434 1913363 3826726 99394411 198788822 2374578137 4749156274 672005612771 1344011225542