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1344011232536 = 23723428600083
BaseRepresentation
bin10011100011101101010…
…011111110010100011000
311202111010110020201022122
4103203231103332110120
5134010013333420121
62505232533040412
7166046564660600
oct23435523762430
94674113221278
101344011232536
11478aa0336645
1219858a786108
1399980201c7b
144909c791c00
1524e62b505ab
hex138ed4fe518

1344011232536 has 24 divisors (see below), whose sum is σ = 2931453071820. Its totient is φ = 576004813776.

The previous prime is 1344011232533. The next prime is 1344011232637. The reversal of 1344011232536 is 6352321104431.

It is a junction number, because it is equal to n+sod(n) for n = 1344011232496 and 1344011232505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344011232533) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1714299650 + ... + 1714300433.

Almost surely, 21344011232536 is an apocalyptic number.

It is an amenable number.

1344011232536 is an abundant number, since it is smaller than the sum of its proper divisors (1587441839284).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1344011232536 is a wasteful number, since it uses less digits than its factorization.

1344011232536 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3428600103 (or 3428600092 counting only the distinct ones).

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 1344011232536 its reverse (6352321104431), we get a palindrome (7696332336967).

The spelling of 1344011232536 in words is "one trillion, three hundred forty-four billion, eleven million, two hundred thirty-two thousand, five hundred thirty-six".

Divisors: 1 2 4 7 8 14 28 49 56 98 196 392 3428600083 6857200166 13714400332 24000200581 27428800664 48000401162 96000802324 168001404067 192001604648 336002808134 672005616268 1344011232536