134401281751 has 4 divisors (see below), whose sum is σ = 146619580104. Its totient is φ = 122182983400.

The previous prime is 134401281697. The next prime is 134401281757. The reversal of 134401281751 is 157182104431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134401281751 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134401281751.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134401281757) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6109149160 + ... + 6109149181.

It is an arithmetic number, because the mean of its divisors is an integer number (36654895026).

Almost surely, 2^134401281751 is an apocalyptic number.

134401281751 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

134401281751 is a deficient number, since it is larger than the sum of its proper divisors (12218298353).

134401281751 is a wasteful number, since it uses less digits than its factorization.

134401281751 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12218298352.

The product of its (nonzero) digits is 26880, while the sum is 37.

The spelling of 134401281751 in words is "one hundred thirty-four billion, four hundred one million, two hundred eighty-one thousand, seven hundred fifty-one".