1344013133 has 2 divisors, whose sum is σ = 1344013134. Its totient is φ = 1344013132.

The previous prime is 1344013103. The next prime is 1344013159. The reversal of 1344013133 is 3313104431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1075643209 + 268369924 = 32797^2 + 16382^2 .

It is a cyclic number.

It is not a de Polignac number, because 1344013133 - 2²² = 1339818829 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1344013099 and 1344013108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1344013103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672006566 + 672006567.

It is an arithmetic number, because the mean of its divisors is an integer number (672006567).

Almost surely, 2^1344013133 is an apocalyptic number.

It is an amenable number.

1344013133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344013133 is an equidigital number, since it uses as much as digits as its factorization.

1344013133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

The square root of 1344013133 is about 36660.7846751812. The cubic root of 1344013133 is about 1103.5732650796.

Adding to 1344013133 its reverse (3313104431), we get a palindrome (4657117564).

The spelling of 1344013133 in words is "one billion, three hundred forty-four million, thirteen thousand, one hundred thirty-three".