134402509 has 2 divisors, whose sum is σ = 134402510. Its totient is φ = 134402508.

The previous prime is 134402507. The next prime is 134402557. The reversal of 134402509 is 905204431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127193284 + 7209225 = 11278^2 + 2685^2 .

It is an emirp because it is prime and its reverse (905204431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134402509 - 2¹ = 134402507 is a prime.

Together with 134402507, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134402507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67201254 + 67201255.

It is an arithmetic number, because the mean of its divisors is an integer number (67201255).

Almost surely, 2^134402509 is an apocalyptic number.

It is an amenable number.

134402509 is a deficient number, since it is larger than the sum of its proper divisors (1).

134402509 is an equidigital number, since it uses as much as digits as its factorization.

134402509 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

The square root of 134402509 is about 11593.2096073521. The cubic root of 134402509 is about 512.2348534485.

The spelling of 134402509 in words is "one hundred thirty-four million, four hundred two thousand, five hundred nine".