Base | Representation |
---|---|
bin | 11110100011110100100011… |
… | …001000100100010111111111 |
3 | 122121212210122020021002222110 |
4 | 132203310203020210113333 |
5 | 120104024321231324211 |
6 | 1153503515234545103 |
7 | 40211203442102502 |
oct | 3643644310442777 |
9 | 577783566232873 |
10 | 134403001042431 |
11 | 39908aa1233850 |
12 | 130a8251138193 |
13 | 59cc1c1679ab4 |
14 | 25291d6099139 |
15 | 10811e5649ea6 |
hex | 7a3d232245ff |
134403001042431 has 8 divisors (see below), whose sum is σ = 195495274243584. Its totient is φ = 81456364268120.
The previous prime is 134403001042421. The next prime is 134403001042441. The reversal of 134403001042431 is 134240100304431.
It is an interprime number because it is at equal distance from previous prime (134403001042421) and next prime (134403001042441).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 134403001042431 - 217 = 134403000911359 is a prime.
It is a super-5 number, since 5×1344030010424315 (a number of 72 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134403001042411) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2036409106671 + ... + 2036409106736.
It is an arithmetic number, because the mean of its divisors is an integer number (24436909280448).
Almost surely, 2134403001042431 is an apocalyptic number.
134403001042431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
134403001042431 is a deficient number, since it is larger than the sum of its proper divisors (61092273201153).
134403001042431 is a wasteful number, since it uses less digits than its factorization.
134403001042431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4072818213421.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 134403001042431 its reverse (134240100304431), we get a palindrome (268643101346862).
The spelling of 134403001042431 in words is "one hundred thirty-four trillion, four hundred three billion, one million, forty-two thousand, four hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •