13440313100 has 72 divisors (see below), whose sum is σ = 30921979200. Its totient is φ = 5056430400.

The previous prime is 13440313091. The next prime is 13440313109. The reversal of 13440313100 is 131304431.

It is an interprime number because it is at equal distance from previous prime (13440313091) and next prime (13440313109).

It is a super-2 number, since 2×13440313100² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (13440313109) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 238655 + ... + 289545.

Almost surely, 2^13440313100 is an apocalyptic number.

13440313100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13440313100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15460989600).

13440313100 is an abundant number, since it is smaller than the sum of its proper divisors (17481666100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13440313100 is a wasteful number, since it uses less digits than its factorization.

13440313100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51063 (or 51056 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13440313100 its reverse (131304431), we get a palindrome (13571617531).

The spelling of 13440313100 in words is "thirteen billion, four hundred forty million, three hundred thirteen thousand, one hundred".