13441131200000 has 720 divisors, whose sum is σ = 39313675513728. Its totient is φ = 4577126400000.

The previous prime is 13441131199987. The next prime is 13441131200017. The reversal of 13441131200000 is 213114431.

It is a super-2 number, since 2×13441131200000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 13563199505 + ... + 13563200495.

Almost surely, 2^{13441131200000} is an apocalyptic number.

13441131200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13441131200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19656837756864).

13441131200000 is an abundant number, since it is smaller than the sum of its proper divisors (25872544313728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13441131200000 is an frugal number, since it uses more digits than its factorization.

13441131200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1221 (or 1178 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13441131200000 its reverse (213114431), we get a palindrome (13441344314431).

The spelling of 13441131200000 in words is "thirteen trillion, four hundred forty-one billion, one hundred thirty-one million, two hundred thousand".