Base | Representation |
---|---|
bin | 1100001110011001101100… |
… | …1000011100010000010111 |
3 | 1202121000000002210102121202 |
4 | 3003212123020130100113 |
5 | 3230211301132204201 |
6 | 44330544300103115 |
7 | 2555056162222046 |
oct | 303463310342027 |
9 | 52530002712552 |
10 | 13441555350551 |
11 | 4312593636009 |
12 | 1611091834a9b |
13 | 7666c167ab83 |
14 | 34680918655d |
15 | 1849a4396c6b |
hex | c399b21c417 |
13441555350551 has 4 divisors (see below), whose sum is σ = 14232235077072. Its totient is φ = 12650875624032.
The previous prime is 13441555350539. The next prime is 13441555350637. The reversal of 13441555350551 is 15505355514431.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13441555350551 - 214 = 13441555334167 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13441555350496 and 13441555350505.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13441555350151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 395339863235 + ... + 395339863268.
It is an arithmetic number, because the mean of its divisors is an integer number (3558058769268).
Almost surely, 213441555350551 is an apocalyptic number.
13441555350551 is a deficient number, since it is larger than the sum of its proper divisors (790679726521).
13441555350551 is an equidigital number, since it uses as much as digits as its factorization.
13441555350551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 790679726520.
The product of its (nonzero) digits is 2250000, while the sum is 47.
The spelling of 13441555350551 in words is "thirteen trillion, four hundred forty-one billion, five hundred fifty-five million, three hundred fifty thousand, five hundred fifty-one".
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