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13441555350551 = 17790679726503
BaseRepresentation
bin1100001110011001101100…
…1000011100010000010111
31202121000000002210102121202
43003212123020130100113
53230211301132204201
644330544300103115
72555056162222046
oct303463310342027
952530002712552
1013441555350551
114312593636009
121611091834a9b
137666c167ab83
1434680918655d
151849a4396c6b
hexc399b21c417

13441555350551 has 4 divisors (see below), whose sum is σ = 14232235077072. Its totient is φ = 12650875624032.

The previous prime is 13441555350539. The next prime is 13441555350637. The reversal of 13441555350551 is 15505355514431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13441555350551 - 214 = 13441555334167 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13441555350496 and 13441555350505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13441555350151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 395339863235 + ... + 395339863268.

It is an arithmetic number, because the mean of its divisors is an integer number (3558058769268).

Almost surely, 213441555350551 is an apocalyptic number.

13441555350551 is a deficient number, since it is larger than the sum of its proper divisors (790679726521).

13441555350551 is an equidigital number, since it uses as much as digits as its factorization.

13441555350551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 790679726520.

The product of its (nonzero) digits is 2250000, while the sum is 47.

The spelling of 13441555350551 in words is "thirteen trillion, four hundred forty-one billion, five hundred fifty-five million, three hundred fifty thousand, five hundred fifty-one".

Divisors: 1 17 790679726503 13441555350551