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13442114111 = 71918695569
BaseRepresentation
bin11001000010011011…
…00110001000111111
31021200210201011000012
430201031212020333
5210012140122421
610101503053435
7654052041026
oct144115461077
937623634005
1013442114111
1157787a5318
1227318a127b
131362b6a19a
149173738bd
1553a18395b
hex32136623f

13442114111 has 4 divisors (see below), whose sum is σ = 13460810400. Its totient is φ = 13423417824.

The previous prime is 13442114093. The next prime is 13442114131. The reversal of 13442114111 is 11141124431.

13442114111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13442114111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13442114131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9347066 + ... + 9348503.

It is an arithmetic number, because the mean of its divisors is an integer number (3365202600).

Almost surely, 213442114111 is an apocalyptic number.

13442114111 is a deficient number, since it is larger than the sum of its proper divisors (18696289).

13442114111 is an equidigital number, since it uses as much as digits as its factorization.

13442114111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18696288.

The product of its digits is 384, while the sum is 23.

Adding to 13442114111 its reverse (11141124431), we get a palindrome (24583238542).

The spelling of 13442114111 in words is "thirteen billion, four hundred forty-two million, one hundred fourteen thousand, one hundred eleven".

Divisors: 1 719 18695569 13442114111