1344214013 has 4 divisors (see below), whose sum is σ = 1375474848. Its totient is φ = 1312953180.

The previous prime is 1344213989. The next prime is 1344214031. The reversal of 1344214013 is 3104124431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3104124431 = 55331 ⋅56101.

It is a cyclic number.

It is not a de Polignac number, because 1344214013 - 2²⁴ = 1327436797 is a prime.

It is a super-2 number, since 2×1344214013² = 3613822625491128338, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1344214013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344214063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15630353 + ... + 15630438.

It is an arithmetic number, because the mean of its divisors is an integer number (343868712).

Almost surely, 2^1344214013 is an apocalyptic number.

It is an amenable number.

1344214013 is a deficient number, since it is larger than the sum of its proper divisors (31260835).

1344214013 is an equidigital number, since it uses as much as digits as its factorization.

1344214013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31260834.

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 1344214013 is about 36663.5242850438. The cubic root of 1344214013 is about 1103.6282433999.

Adding to 1344214013 its reverse (3104124431), we get a palindrome (4448338444).

The spelling of 1344214013 in words is "one billion, three hundred forty-four million, two hundred fourteen thousand, thirteen".