Base | Representation |
---|---|
bin | 1100001110011100100101… |
… | …1000100010011010111000 |
3 | 1202121002000011220212101112 |
4 | 3003213021120202122320 |
5 | 3230214343304301130 |
6 | 44331153255535452 |
7 | 2555114333660435 |
oct | 303471130423270 |
9 | 52532004825345 |
10 | 13442331322040 |
11 | 4312951654965 |
12 | 161126968a588 |
13 | 7667b6369aba |
14 | 346880258b8c |
15 | 1849ec574495 |
hex | c39c96226b8 |
13442331322040 has 64 divisors (see below), whose sum is σ = 30491528371200. Its totient is φ = 5333171493888.
The previous prime is 13442331322031. The next prime is 13442331322103. The reversal of 13442331322040 is 4022313324431.
It is a junction number, because it is equal to n+sod(n) for n = 13442331321988 and 13442331322006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18795482 + ... + 19497558.
It is an arithmetic number, because the mean of its divisors is an integer number (476430130800).
Almost surely, 213442331322040 is an apocalyptic number.
13442331322040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13442331322040 is an abundant number, since it is smaller than the sum of its proper divisors (17049197049160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13442331322040 is a wasteful number, since it uses less digits than its factorization.
13442331322040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 705984 (or 705980 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 13442331322040 its reverse (4022313324431), we get a palindrome (17464644646471).
The spelling of 13442331322040 in words is "thirteen trillion, four hundred forty-two billion, three hundred thirty-one million, three hundred twenty-two thousand, forty".
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