Base | Representation |
---|---|
bin | 1100001110011100110110… |
… | …0000001010110101011111 |
3 | 1202121002011222221222200111 |
4 | 3003213031200022311133 |
5 | 3230220014002301310 |
6 | 44331204205110451 |
7 | 2555116133254552 |
oct | 303471540126537 |
9 | 52532158858614 |
10 | 13442400431455 |
11 | 4312987667886 |
12 | 1611288858427 |
13 | 7667c7786148 |
14 | 3468894c8699 |
15 | 184a0367628a |
hex | c39cd80ad5f |
13442400431455 has 32 divisors (see below), whose sum is σ = 16412247371520. Its totient is φ = 10568007648000.
The previous prime is 13442400431441. The next prime is 13442400431477. The reversal of 13442400431455 is 55413400424431.
It is not a de Polignac number, because 13442400431455 - 211 = 13442400429407 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 52032712 + ... + 52290418.
It is an arithmetic number, because the mean of its divisors is an integer number (512882730360).
Almost surely, 213442400431455 is an apocalyptic number.
13442400431455 is a deficient number, since it is larger than the sum of its proper divisors (2969846940065).
13442400431455 is a wasteful number, since it uses less digits than its factorization.
13442400431455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 258519.
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 13442400431455 its reverse (55413400424431), we get a palindrome (68855800855886).
The spelling of 13442400431455 in words is "thirteen trillion, four hundred forty-two billion, four hundred million, four hundred thirty-one thousand, four hundred fifty-five".
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