13442401021341 has 4 divisors (see below), whose sum is σ = 17923201361792. Its totient is φ = 8961600680892.

The previous prime is 13442401021339. The next prime is 13442401021451. The reversal of 13442401021341 is 14312010424431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13442401021341 - 2¹ = 13442401021339 is a prime.

It is a super-3 number, since 3×13442401021341³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13442401021299 and 13442401021308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13442401021321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2240400170221 + ... + 2240400170226.

It is an arithmetic number, because the mean of its divisors is an integer number (4480800340448).

Almost surely, 2^{13442401021341} is an apocalyptic number.

It is an amenable number.

13442401021341 is a deficient number, since it is larger than the sum of its proper divisors (4480800340451).

13442401021341 is an equidigital number, since it uses as much as digits as its factorization.

13442401021341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4480800340450.

The product of its (nonzero) digits is 9216, while the sum is 30.

Adding to 13442401021341 its reverse (14312010424431), we get a palindrome (27754411445772).

The spelling of 13442401021341 in words is "thirteen trillion, four hundred forty-two billion, four hundred one million, twenty-one thousand, three hundred forty-one".