Base | Representation |
---|---|
bin | 10011100011111110110… |
… | …010100001110110001111 |
3 | 11202111212212222221222221 |
4 | 103203332302201312033 |
5 | 134011113420030210 |
6 | 2505322005520211 |
7 | 166060055222002 |
oct | 23437662416617 |
9 | 4674785887887 |
10 | 1344304455055 |
11 | 479130901001 |
12 | 198650a13067 |
13 | 999c8b98c13 |
14 | 490c96bd539 |
15 | 24e7d7711da |
hex | 138feca1d8f |
1344304455055 has 32 divisors (see below), whose sum is σ = 1716260515200. Its totient is φ = 1008739049472.
The previous prime is 1344304454993. The next prime is 1344304455127. The reversal of 1344304455055 is 5505544034431.
It is a cyclic number.
It is not a de Polignac number, because 1344304455055 - 29 = 1344304454543 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 663091 + ... + 1768699.
It is an arithmetic number, because the mean of its divisors is an integer number (53633141100).
Almost surely, 21344304455055 is an apocalyptic number.
1344304455055 is a deficient number, since it is larger than the sum of its proper divisors (371956060145).
1344304455055 is a wasteful number, since it uses less digits than its factorization.
1344304455055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1105843.
The product of its (nonzero) digits is 1440000, while the sum is 43.
Adding to 1344304455055 its reverse (5505544034431), we get a palindrome (6849848489486).
The spelling of 1344304455055 in words is "one trillion, three hundred forty-four billion, three hundred four million, four hundred fifty-five thousand, fifty-five".
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