Base | Representation |
---|---|
bin | 10011100100000000111… |
… | …100100110110101010111 |
3 | 11202111222102002220222111 |
4 | 103210000330212311113 |
5 | 134011202201320401 |
6 | 2505325341411451 |
7 | 166061004665365 |
oct | 23440074466527 |
9 | 4674872086874 |
10 | 1344340651351 |
11 | 47914a2838a5 |
12 | 198660b69b87 |
13 | 99a03530349 |
14 | 490d0422635 |
15 | 24e81a20e51 |
hex | 13900f26d57 |
1344340651351 has 4 divisors (see below), whose sum is σ = 1402790244912. Its totient is φ = 1285891057792.
The previous prime is 1344340651349. The next prime is 1344340651373. The reversal of 1344340651351 is 1531560434431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1344340651351 - 21 = 1344340651349 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1344340651301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29224796746 + ... + 29224796791.
It is an arithmetic number, because the mean of its divisors is an integer number (350697561228).
Almost surely, 21344340651351 is an apocalyptic number.
1344340651351 is a deficient number, since it is larger than the sum of its proper divisors (58449593561).
1344340651351 is an equidigital number, since it uses as much as digits as its factorization.
1344340651351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58449593560.
The product of its (nonzero) digits is 259200, while the sum is 40.
The spelling of 1344340651351 in words is "one trillion, three hundred forty-four billion, three hundred forty million, six hundred fifty-one thousand, three hundred fifty-one".
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