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13444003441 = 111222182131
BaseRepresentation
bin11001000010101001…
…10011011001110001
31021200221021010200101
430201110303121301
5210013131102231
610102011352401
7654104100211
oct144124633161
937627233611
1013444003441
115779875850
122732452701
13136337c12b
14917706241
1553a408661
hex321533671

13444003441 has 4 divisors (see below), whose sum is σ = 14666185584. Its totient is φ = 12221821300.

The previous prime is 13444003409. The next prime is 13444003471. The reversal of 13444003441 is 14430044431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13444003441 - 25 = 13444003409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13444003471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 611091055 + ... + 611091076.

It is an arithmetic number, because the mean of its divisors is an integer number (3666546396).

Almost surely, 213444003441 is an apocalyptic number.

13444003441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13444003441 is a deficient number, since it is larger than the sum of its proper divisors (1222182143).

13444003441 is a wasteful number, since it uses less digits than its factorization.

13444003441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1222182142.

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 13444003441 its reverse (14430044431), we get a palindrome (27874047872).

The spelling of 13444003441 in words is "thirteen billion, four hundred forty-four million, three thousand, four hundred forty-one".

Divisors: 1 11 1222182131 13444003441