Base | Representation |
---|---|
bin | 11001000010101001… |
… | …10011011010001111 |
3 | 1021200221021010201111 |
4 | 30201110303122033 |
5 | 210013131102341 |
6 | 10102011352451 |
7 | 654104100253 |
oct | 144124633217 |
9 | 37627233644 |
10 | 13444003471 |
11 | 5779875878 |
12 | 2732452727 |
13 | 136337c152 |
14 | 917706263 |
15 | 53a408681 |
hex | 32153368f |
13444003471 has 2 divisors, whose sum is σ = 13444003472. Its totient is φ = 13444003470.
The previous prime is 13444003409. The next prime is 13444003481. The reversal of 13444003471 is 17430044431.
It is a happy number.
13444003471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (17430044431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13444003471 - 27 = 13444003343 is a prime.
It is a super-3 number, since 3×134440034713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13444003481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6722001735 + 6722001736.
It is an arithmetic number, because the mean of its divisors is an integer number (6722001736).
Almost surely, 213444003471 is an apocalyptic number.
13444003471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13444003471 is an equidigital number, since it uses as much as digits as its factorization.
13444003471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
The spelling of 13444003471 in words is "thirteen billion, four hundred forty-four million, three thousand, four hundred seventy-one".
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