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1344413411293 is a prime number
BaseRepresentation
bin10011100100000101010…
…010001010011111011101
311202112011111000111212011
4103210011102022133131
5134011324313130133
62505340501111221
7166062550305451
oct23440522123735
94675144014764
101344413411293
1147918735a487
121986813b8511
1399a15627174
14490d9d62661
1524e880e46cd
hex1390548a7dd

1344413411293 has 2 divisors, whose sum is σ = 1344413411294. Its totient is φ = 1344413411292.

The previous prime is 1344413411239. The next prime is 1344413411333. The reversal of 1344413411293 is 3921143144431.

Together with previous prime (1344413411239) it forms an Ormiston pair, because they use the same digits, order apart.

It is an a-pointer prime, because the next prime (1344413411333) can be obtained adding 1344413411293 to its sum of digits (40).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1062965124004 + 281448287289 = 1031002^2 + 530517^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1344413411293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1344413411213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672206705646 + 672206705647.

It is an arithmetic number, because the mean of its divisors is an integer number (672206705647).

Almost surely, 21344413411293 is an apocalyptic number.

It is an amenable number.

1344413411293 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344413411293 is an equidigital number, since it uses as much as digits as its factorization.

1344413411293 is an evil number, because the sum of its binary digits is even.

The product of its digits is 124416, while the sum is 40.

The spelling of 1344413411293 in words is "one trillion, three hundred forty-four billion, four hundred thirteen million, four hundred eleven thousand, two hundred ninety-three".