Base | Representation |
---|---|
bin | 10011100100101110100… |
… | …000110100101110111111 |
3 | 11202120221200120222002020 |
4 | 103210232200310232333 |
5 | 134014233402321231 |
6 | 2505533250531223 |
7 | 166115646605460 |
oct | 23445640645677 |
9 | 4676850528066 |
10 | 1345105120191 |
11 | 479501856628 |
12 | 198834b96b13 |
13 | 99ac5a22781 |
14 | 49163b7cd67 |
15 | 24ec8bca396 |
hex | 1392e834bbf |
1345105120191 has 64 divisors (see below), whose sum is σ = 2131752038400. Its totient is φ = 738149400576.
The previous prime is 1345105120147. The next prime is 1345105120273. The reversal of 1345105120191 is 1910215015431.
It is not a de Polignac number, because 1345105120191 - 214 = 1345105103807 is a prime.
It is a super-3 number, since 3×13451051201913 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1345105124191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 112526871 + ... + 112538823.
It is an arithmetic number, because the mean of its divisors is an integer number (33308625600).
Almost surely, 21345105120191 is an apocalyptic number.
1345105120191 is a deficient number, since it is larger than the sum of its proper divisors (786646918209).
1345105120191 is a wasteful number, since it uses less digits than its factorization.
1345105120191 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12968.
The product of its (nonzero) digits is 5400, while the sum is 33.
The spelling of 1345105120191 in words is "one trillion, three hundred forty-five billion, one hundred five million, one hundred twenty thousand, one hundred ninety-one".
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