Base | Representation |
---|---|
bin | 11110100110000001010001… |
… | …011010011010000101000110 |
3 | 122122102020122200002211100212 |
4 | 132212001101122122011012 |
5 | 120114013244414414100 |
6 | 1154101144550235422 |
7 | 40225133031241142 |
oct | 3646012132320506 |
9 | 578366580084325 |
10 | 134554101326150 |
11 | 3996708a420390 |
12 | 131115a0355b72 |
13 | 5a10521b790bc |
14 | 253264ba20222 |
15 | 10850dab19635 |
hex | 7a605169a146 |
134554101326150 has 48 divisors (see below), whose sum is σ = 273024760796928. Its totient is φ = 48928359636000.
The previous prime is 134554101326119. The next prime is 134554101326171. The reversal of 134554101326150 is 51623101455431.
It is a junction number, because it is equal to n+sod(n) for n = 134554101326098 and 134554101326107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 70126055 + ... + 72019245.
It is an arithmetic number, because the mean of its divisors is an integer number (5688015849936).
Almost surely, 2134554101326150 is an apocalyptic number.
134554101326150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
134554101326150 is an abundant number, since it is smaller than the sum of its proper divisors (138470659470778).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134554101326150 is a wasteful number, since it uses less digits than its factorization.
134554101326150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2022437 (or 2022432 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 41.
The spelling of 134554101326150 in words is "one hundred thirty-four trillion, five hundred fifty-four billion, one hundred one million, three hundred twenty-six thousand, one hundred fifty".
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