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134624433560 = 2353365610839
BaseRepresentation
bin111110101100000111…
…1011101010110011000
3110212111012121210212212
41331120033131112120
54201202323333220
6141502352454252
712504055542641
oct1753017352630
9425435553785
10134624433560
1152103a8a551
122211154a388
13c905c98256
1467317266c8
15377dd310c5
hex1f583dd598

134624433560 has 16 divisors (see below), whose sum is σ = 302904975600. Its totient is φ = 53849773408.

The previous prime is 134624433469. The next prime is 134624433577. The reversal of 134624433560 is 65334426431.

It is a super-2 number, since 2×1346244335602 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1682805380 + ... + 1682805459.

It is an arithmetic number, because the mean of its divisors is an integer number (18931560975).

Almost surely, 2134624433560 is an apocalyptic number.

134624433560 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

134624433560 is an abundant number, since it is smaller than the sum of its proper divisors (168280542040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134624433560 is a wasteful number, since it uses less digits than its factorization.

134624433560 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3365610850 (or 3365610846 counting only the distinct ones).

The product of its (nonzero) digits is 622080, while the sum is 41.

Adding to 134624433560 its reverse (65334426431), we get a palindrome (199958859991).

The spelling of 134624433560 in words is "one hundred thirty-four billion, six hundred twenty-four million, four hundred thirty-three thousand, five hundred sixty".

Divisors: 1 2 4 5 8 10 20 40 3365610839 6731221678 13462443356 16828054195 26924886712 33656108390 67312216780 134624433560