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1349113312280 = 23533727832807
BaseRepresentation
bin10011101000011101011…
…010110111010000011000
311202222022000201012222002
4103220131122313100120
5134100441001443110
62511435112220132
7166320166641626
oct23503532672030
94688260635862
101349113312280
11480179325678
1219957339a648
139a2b4251b76
1449424226516
1525160a1caa5
hex13a1d6b7418

1349113312280 has 16 divisors (see below), whose sum is σ = 3035504952720. Its totient is φ = 539645324896.

The previous prime is 1349113312249. The next prime is 1349113312291. The reversal of 1349113312280 is 822133119431.

It is a super-2 number, since 2×13491133122802 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16863916364 + ... + 16863916443.

It is an arithmetic number, because the mean of its divisors is an integer number (189719059545).

Almost surely, 21349113312280 is an apocalyptic number.

1349113312280 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1349113312280 is an abundant number, since it is smaller than the sum of its proper divisors (1686391640440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1349113312280 is a wasteful number, since it uses less digits than its factorization.

1349113312280 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33727832818 (or 33727832814 counting only the distinct ones).

The product of its (nonzero) digits is 31104, while the sum is 38.

The spelling of 1349113312280 in words is "one trillion, three hundred forty-nine billion, one hundred thirteen million, three hundred twelve thousand, two hundred eighty".

Divisors: 1 2 4 5 8 10 20 40 33727832807 67455665614 134911331228 168639164035 269822662456 337278328070 674556656140 1349113312280