Base | Representation |
---|---|
bin | 1100010001011100010000… |
… | …0100111100110100001110 |
3 | 1202202222210212021110220002 |
4 | 3010113010010330310032 |
5 | 3232040231132040000 |
6 | 44410542520324302 |
7 | 2561615331516113 |
oct | 304270404746416 |
9 | 52688725243802 |
10 | 13493781908750 |
11 | 4332754118200 |
12 | 161b228313692 |
13 | 76b5c57ba750 |
14 | 3491614a890a |
15 | 18600e4528d5 |
hex | c45c413cd0e |
13493781908750 has 240 divisors, whose sum is σ = 30175967399424. Its totient is φ = 4493633760000.
The previous prime is 13493781908683. The next prime is 13493781908753. The reversal of 13493781908750 is 5780918739431.
It is a Harshad number since it is a multiple of its sum of digits (65).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13493781908753) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 249686732 + ... + 249740768.
Almost surely, 213493781908750 is an apocalyptic number.
13493781908750 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13493781908750 is an abundant number, since it is smaller than the sum of its proper divisors (16682185490674).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13493781908750 is a wasteful number, since it uses less digits than its factorization.
13493781908750 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 54221 (or 54195 counting only the distinct ones).
The product of its (nonzero) digits is 45722880, while the sum is 65.
The spelling of 13493781908750 in words is "thirteen trillion, four hundred ninety-three billion, seven hundred eighty-one million, nine hundred eight thousand, seven hundred fifty".
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