Base | Representation |
---|---|
bin | 110011011110… |
… | …100000011101 |
3 | 221101120200221 |
4 | 303132200131 |
5 | 11423304201 |
6 | 1201121341 |
7 | 222461662 |
oct | 63364035 |
9 | 27346627 |
10 | 13494301 |
11 | 7687517 |
12 | 4629251 |
13 | 2a461c2 |
14 | 1b13a69 |
15 | 12b84a1 |
hex | cde81d |
13494301 has 2 divisors, whose sum is σ = 13494302. Its totient is φ = 13494300.
The previous prime is 13494293. The next prime is 13494317. The reversal of 13494301 is 10349431.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8323225 + 5171076 = 2885^2 + 2274^2 .
It is an emirp because it is prime and its reverse (10349431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13494301 - 23 = 13494293 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13494391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6747150 + 6747151.
It is an arithmetic number, because the mean of its divisors is an integer number (6747151).
Almost surely, 213494301 is an apocalyptic number.
It is an amenable number.
13494301 is a deficient number, since it is larger than the sum of its proper divisors (1).
13494301 is an equidigital number, since it uses as much as digits as its factorization.
13494301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
The square root of 13494301 is about 3673.4589966406. The cubic root of 13494301 is about 238.0766471586.
It can be divided in two parts, 1349430 and 1, that added together give a palindrome (1349431).
The spelling of 13494301 in words is "thirteen million, four hundred ninety-four thousand, three hundred one".
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