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1350113537 is a prime number
BaseRepresentation
bin101000001111001…
…0001100100000001
310111002110212121002
41100132101210001
510231112113122
6341545341345
745312530033
oct12036214401
93432425532
101350113537
11633116313
12318197855
13186932c66
14cb447c53
157d7dd992
hex50791901

1350113537 has 2 divisors, whose sum is σ = 1350113538. Its totient is φ = 1350113536.

The previous prime is 1350113507. The next prime is 1350113539. The reversal of 1350113537 is 7353110531.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 696748816 + 653364721 = 26396^2 + 25561^2 .

It is a cyclic number.

It is not a de Polignac number, because 1350113537 - 214 = 1350097153 is a prime.

Together with 1350113539, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1350113539) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 675056768 + 675056769.

It is an arithmetic number, because the mean of its divisors is an integer number (675056769).

Almost surely, 21350113537 is an apocalyptic number.

It is an amenable number.

1350113537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1350113537 is an equidigital number, since it uses as much as digits as its factorization.

1350113537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4725, while the sum is 29.

The square root of 1350113537 is about 36743.8911521358. The cubic root of 1350113537 is about 1105.2404319743.

The spelling of 1350113537 in words is "one billion, three hundred fifty million, one hundred thirteen thousand, five hundred thirty-seven".