Base | Representation |
---|---|
bin | 11001001001011110… |
… | …00111100001011101 |
3 | 1021211220221201012202 |
4 | 30210233013201131 |
5 | 210122303430440 |
6 | 10111414141245 |
7 | 655400406023 |
oct | 144457074135 |
9 | 37756851182 |
10 | 13501233245 |
11 | 57a9104405 |
12 | 2749651825 |
13 | 1372199216 |
14 | 921162713 |
15 | 540460615 |
hex | 324bc785d |
13501233245 has 4 divisors (see below), whose sum is σ = 16201479900. Its totient is φ = 10800986592.
The previous prime is 13501233241. The next prime is 13501233257. The reversal of 13501233245 is 54233210531.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7815620836 + 5685612409 = 88406^2 + 75403^2 .
It is a cyclic number.
It is not a de Polignac number, because 13501233245 - 22 = 13501233241 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13501233241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1350123320 + ... + 1350123329.
It is an arithmetic number, because the mean of its divisors is an integer number (4050369975).
Almost surely, 213501233245 is an apocalyptic number.
It is an amenable number.
13501233245 is a deficient number, since it is larger than the sum of its proper divisors (2700246655).
13501233245 is an equidigital number, since it uses as much as digits as its factorization.
13501233245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2700246654.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 13501233245 its reverse (54233210531), we get a palindrome (67734443776).
The spelling of 13501233245 in words is "thirteen billion, five hundred one million, two hundred thirty-three thousand, two hundred forty-five".
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