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13501315109 is a prime number
BaseRepresentation
bin11001001001011110…
…11011100000100101
31021211221002212111202
430210233123200211
5210122314040414
610111420012245
7655401166502
oct144457334045
937757085452
1013501315109
1157a915a967
122749691085
1313721c7569
149211844a9
155404799de
hex324bdb825

13501315109 has 2 divisors, whose sum is σ = 13501315110. Its totient is φ = 13501315108.

The previous prime is 13501315099. The next prime is 13501315111. The reversal of 13501315109 is 90151310531.

13501315109 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13130868100 + 370447009 = 114590^2 + 19247^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13501315109 is a prime.

It is a Sophie Germain prime.

Together with 13501315111, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13501314109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750657554 + 6750657555.

It is an arithmetic number, because the mean of its divisors is an integer number (6750657555).

Almost surely, 213501315109 is an apocalyptic number.

It is an amenable number.

13501315109 is a deficient number, since it is larger than the sum of its proper divisors (1).

13501315109 is an equidigital number, since it uses as much as digits as its factorization.

13501315109 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2025, while the sum is 29.

The spelling of 13501315109 in words is "thirteen billion, five hundred one million, three hundred fifteen thousand, one hundred nine".