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13501400000 = 26551117192
BaseRepresentation
bin11001001001011111…
…10000001111000000
31021211221021011221212
430210233300033000
5210122324300000
610111421505252
7655402002134
oct144457601700
937757234855
1013501400000
1157a9208720
122749712228
1313722270aa
149211a73c4
15540494c35
hex324bf03c0

13501400000 has 504 divisors, whose sum is σ = 40823918352. Its totient is φ = 4377600000.

The previous prime is 13501399997. The next prime is 13501400009. The reversal of 13501400000 is 410531.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13501400009) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 710599991 + ... + 710600009.

It is an arithmetic number, because the mean of its divisors is an integer number (80999838).

Almost surely, 213501400000 is an apocalyptic number.

13501400000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13501400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20411959176).

13501400000 is an abundant number, since it is smaller than the sum of its proper divisors (27322518352).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13501400000 is an equidigital number, since it uses as much as digits as its factorization.

13501400000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103 (or 54 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 14.

Adding to 13501400000 its reverse (410531), we get a palindrome (13501810531).

The spelling of 13501400000 in words is "thirteen billion, five hundred one million, four hundred thousand".