13501415104231 has 4 divisors (see below), whose sum is σ = 13501425832264. Its totient is φ = 13501404376200.

The previous prime is 13501415104213. The next prime is 13501415104241. The reversal of 13501415104231 is 13240151410531.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13501415104231 - 2²⁹ = 13500878233319 is a prime.

It is a super-2 number, since 2×13501415104231² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13501415104193 and 13501415104202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13501415104241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3179760 + ... + 6092101.

It is an arithmetic number, because the mean of its divisors is an integer number (3375356458066).

Almost surely, 2^{13501415104231} is an apocalyptic number.

13501415104231 is a deficient number, since it is larger than the sum of its proper divisors (10728033).

13501415104231 is an equidigital number, since it uses as much as digits as its factorization.

13501415104231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10728032.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 13501415104231 its reverse (13240151410531), we get a palindrome (26741566514762).

The spelling of 13501415104231 in words is "thirteen trillion, five hundred one billion, four hundred fifteen million, one hundred four thousand, two hundred thirty-one".