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13501440023 is a prime number
BaseRepresentation
bin11001001001011111…
…11010000000010111
31021211221100012212012
430210233322000113
5210122332040043
610111422414435
7655402226621
oct144457720027
937757305765
1013501440023
1157a92357a5
12274973141b
13137223c386
149211b7c11
155404a1a18
hex324bfa017

13501440023 has 2 divisors, whose sum is σ = 13501440024. Its totient is φ = 13501440022.

The previous prime is 13501439999. The next prime is 13501440031. The reversal of 13501440023 is 32004410531.

13501440023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13501440023 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13501440083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6750720011 + 6750720012.

It is an arithmetic number, because the mean of its divisors is an integer number (6750720012).

Almost surely, 213501440023 is an apocalyptic number.

13501440023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13501440023 is an equidigital number, since it uses as much as digits as its factorization.

13501440023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 13501440023 its reverse (32004410531), we get a palindrome (45505850554).

The spelling of 13501440023 in words is "thirteen billion, five hundred one million, four hundred forty thousand, twenty-three".