Base | Representation |
---|---|
bin | 1100010001111100000000… |
… | …0011110011100101110110 |
3 | 1202210210210210220122102210 |
4 | 3010133000003303211312 |
5 | 3232210204413401200 |
6 | 44414512323514250 |
7 | 2562336456012111 |
oct | 304370003634566 |
9 | 52723723818383 |
10 | 13502304434550 |
11 | 4336327937a58 |
12 | 1620a06528986 |
13 | 76c353371919 |
14 | 34972d30d578 |
15 | 18635c765650 |
hex | c47c00f3976 |
13502304434550 has 48 divisors (see below), whose sum is σ = 33486395251392. Its totient is φ = 3600541370400.
The previous prime is 13502304434503. The next prime is 13502304434573. The reversal of 13502304434550 is 5543440320531.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13502304434499 and 13502304434508.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6705045 + ... + 8483055.
It is an arithmetic number, because the mean of its divisors is an integer number (697633234404).
Almost surely, 213502304434550 is an apocalyptic number.
13502304434550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13502304434550 is an abundant number, since it is smaller than the sum of its proper divisors (19984090816842).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13502304434550 is a wasteful number, since it uses less digits than its factorization.
13502304434550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1828653 (or 1828648 counting only the distinct ones).
The product of its (nonzero) digits is 432000, while the sum is 39.
The spelling of 13502304434550 in words is "thirteen trillion, five hundred two billion, three hundred four million, four hundred thirty-four thousand, five hundred fifty".
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