13503113031 has 4 divisors (see below), whose sum is σ = 18004150712. Its totient is φ = 9002075352.

The previous prime is 13503113027. The next prime is 13503113051. The reversal of 13503113031 is 13031130531.

13503113031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13031130531 = 3 ⋅4343710177.

It is not a de Polignac number, because 13503113031 - 2² = 13503113027 is a prime.

It is a super-2 number, since 2×13503113031² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13503112989 and 13503113007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13503113051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2250518836 + ... + 2250518841.

It is an arithmetic number, because the mean of its divisors is an integer number (4501037678).

Almost surely, 2^13503113031 is an apocalyptic number.

13503113031 is a deficient number, since it is larger than the sum of its proper divisors (4501037681).

13503113031 is an equidigital number, since it uses as much as digits as its factorization.

13503113031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4501037680.

The product of its (nonzero) digits is 405, while the sum is 21.

Adding to 13503113031 its reverse (13031130531), we get a palindrome (26534243562).

The spelling of 13503113031 in words is "thirteen billion, five hundred three million, one hundred thirteen thousand, thirty-one".