Base | Representation |
---|---|
bin | 1100010010000000000111… |
… | …1111010011010101111110 |
3 | 1202210220122220021010202221 |
4 | 3010200001333103111332 |
5 | 3232214441100101032 |
6 | 44415214155435554 |
7 | 2562406046565652 |
oct | 304400177232576 |
9 | 52726586233687 |
10 | 13503410550142 |
11 | 4336845249a77 |
12 | 1621074a55bba |
13 | 76c49b5840a6 |
14 | 3497d61a0a62 |
15 | 1863c4908597 |
hex | c4801fd357e |
13503410550142 has 8 divisors (see below), whose sum is σ = 20255135806656. Its totient is φ = 6751698614592.
The previous prime is 13503410550137. The next prime is 13503410550193. The reversal of 13503410550142 is 24105501430531.
13503410550142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13503410550098 and 13503410550107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212083 + ... + 5201134.
It is an arithmetic number, because the mean of its divisors is an integer number (2531891975832).
Almost surely, 213503410550142 is an apocalyptic number.
13503410550142 is a deficient number, since it is larger than the sum of its proper divisors (6751725256514).
13503410550142 is a wasteful number, since it uses less digits than its factorization.
13503410550142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6660482.
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 13503410550142 its reverse (24105501430531), we get a palindrome (37608911980673).
The spelling of 13503410550142 in words is "thirteen trillion, five hundred three billion, four hundred ten million, five hundred fifty thousand, one hundred forty-two".
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