Base | Representation |
---|---|
bin | 11110101101010001000000… |
… | …110111101101001000101001 |
3 | 122201011211220212120022202221 |
4 | 132231101000313231020221 |
5 | 120200143034220000131 |
6 | 1155122014540154041 |
7 | 40306121310156433 |
oct | 3655210067551051 |
9 | 581154825508687 |
10 | 135052040000041 |
11 | 3a039280864a8a |
12 | 13191ba6b38921 |
13 | 5a48477c2a088 |
14 | 254c7a7183653 |
15 | 10930307c4411 |
hex | 7ad440ded229 |
135052040000041 has 2 divisors, whose sum is σ = 135052040000042. Its totient is φ = 135052040000040.
The previous prime is 135052040000039. The next prime is 135052040000081. The reversal of 135052040000041 is 140000040250531.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 67749361000000 + 67302679000041 = 8231000^2 + 8203821^2 .
It is an emirp because it is prime and its reverse (140000040250531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135052040000041 - 21 = 135052040000039 is a prime.
Together with 135052040000039, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 135052039999970 and 135052040000015.
It is not a weakly prime, because it can be changed into another prime (135052040000081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67526020000020 + 67526020000021.
It is an arithmetic number, because the mean of its divisors is an integer number (67526020000021).
Almost surely, 2135052040000041 is an apocalyptic number.
It is an amenable number.
135052040000041 is a deficient number, since it is larger than the sum of its proper divisors (1).
135052040000041 is an equidigital number, since it uses as much as digits as its factorization.
135052040000041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 135052040000041 its reverse (140000040250531), we get a palindrome (275052080250572).
The spelling of 135052040000041 in words is "one hundred thirty-five trillion, fifty-two billion, forty million, forty-one", and thus it is an aban number.
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