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135086250335 = 527017250067
BaseRepresentation
bin111110111001111000…
…1001001100101011111
3110220200101121112101212
41331303301021211133
54203124040002320
6142020251055035
712521364116351
oct1756361114537
9426611545355
10135086250335
1152320737303
122222014147b
13c97a87170a
146776bbd0d1
1537a96559c5
hex1f73c4995f

135086250335 has 4 divisors (see below), whose sum is σ = 162103500408. Its totient is φ = 108069000264.

The previous prime is 135086250319. The next prime is 135086250353. The reversal of 135086250335 is 533052680531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135086250335 - 24 = 135086250319 is a prime.

It is a super-2 number, since 2×1350862503352 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135086250292 and 135086250301.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13508625029 + ... + 13508625038.

It is an arithmetic number, because the mean of its divisors is an integer number (40525875102).

Almost surely, 2135086250335 is an apocalyptic number.

135086250335 is a deficient number, since it is larger than the sum of its proper divisors (27017250073).

135086250335 is an equidigital number, since it uses as much as digits as its factorization.

135086250335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27017250072.

The product of its (nonzero) digits is 324000, while the sum is 41.

The spelling of 135086250335 in words is "one hundred thirty-five billion, eighty-six million, two hundred fifty thousand, three hundred thirty-five".

Divisors: 1 5 27017250067 135086250335