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1351102135207 = 11122827466837
BaseRepresentation
bin10011101010010011111…
…101100111101110100111
311210011102122000220010111
4103222103331213232213
5134114024121311312
62512404315433451
7166420366442326
oct23522375475647
94704378026114
101351102135207
11480aa9a28790
12199a29455887
139a5402b4976
14495724120bd
152522a4238a7
hex13a93f67ba7

1351102135207 has 4 divisors (see below), whose sum is σ = 1473929602056. Its totient is φ = 1228274668360.

The previous prime is 1351102135199. The next prime is 1351102135211. The reversal of 1351102135207 is 7025312011531.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1351102135207 - 23 = 1351102135199 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1351102132207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61413733408 + ... + 61413733429.

It is an arithmetic number, because the mean of its divisors is an integer number (368482400514).

Almost surely, 21351102135207 is an apocalyptic number.

1351102135207 is a deficient number, since it is larger than the sum of its proper divisors (122827466849).

1351102135207 is a wasteful number, since it uses less digits than its factorization.

1351102135207 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122827466848.

The product of its (nonzero) digits is 6300, while the sum is 31.

Adding to 1351102135207 its reverse (7025312011531), we get a palindrome (8376414146738).

The spelling of 1351102135207 in words is "one trillion, three hundred fifty-one billion, one hundred two million, one hundred thirty-five thousand, two hundred seven".

Divisors: 1 11 122827466837 1351102135207