Base | Representation |
---|---|
bin | 11001001010101100… |
… | …11100010100011101 |
3 | 1021212122100110020011 |
4 | 30211112130110131 |
5 | 210132423321140 |
6 | 10112423123221 |
7 | 655554132601 |
oct | 144526342435 |
9 | 37778313204 |
10 | 13511542045 |
11 | 5803a05581 |
12 | 2750ba3511 |
13 | 13743684c1 |
14 | 922687501 |
15 | 5412e9cea |
hex | 32559c51d |
13511542045 has 8 divisors (see below), whose sum is σ = 16736878080. Its totient is φ = 10460548560.
The previous prime is 13511542003. The next prime is 13511542123. The reversal of 13511542045 is 54024511531.
13511542045 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13511542045 - 225 = 13477987613 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a junction number, because it is equal to n+sod(n) for n = 13511541998 and 13511542016.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43585465 + ... + 43585774.
It is an arithmetic number, because the mean of its divisors is an integer number (2092109760).
Almost surely, 213511542045 is an apocalyptic number.
It is an amenable number.
13511542045 is a deficient number, since it is larger than the sum of its proper divisors (3225336035).
13511542045 is an equidigital number, since it uses as much as digits as its factorization.
13511542045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 87171275.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 13511542045 in words is "thirteen billion, five hundred eleven million, five hundred forty-two thousand, forty-five".
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