Base | Representation |
---|---|
bin | 10000000111001… |
… | …00010111001100 |
3 | 100102022111012101 |
4 | 20003210113030 |
5 | 234044344400 |
6 | 21224444444 |
7 | 3230532235 |
oct | 1003442714 |
9 | 312274171 |
10 | 135153100 |
11 | 6a321585 |
12 | 39319724 |
13 | 22001164 |
14 | 13d4208c |
15 | bcea56a |
hex | 80e45cc |
135153100 has 36 divisors (see below), whose sum is σ = 295074864. Its totient is φ = 53730880.
The previous prime is 135153071. The next prime is 135153101. The reversal of 135153100 is 1351531.
It is a super-2 number, since 2×1351531002 = 36532720879220000, which contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (135153101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12654 + ... + 20746.
It is an arithmetic number, because the mean of its divisors is an integer number (8196524).
Almost surely, 2135153100 is an apocalyptic number.
135153100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 135153100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (147537432).
135153100 is an abundant number, since it is smaller than the sum of its proper divisors (159921764).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135153100 is a wasteful number, since it uses less digits than its factorization.
135153100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8274 (or 8267 counting only the distinct ones).
The product of its (nonzero) digits is 225, while the sum is 19.
The square root of 135153100 is about 11625.5365467577. The cubic root of 135153100 is about 513.1866346800.
Multiplying 135153100 by its reverse (1351531), we get a square (182663604396100 = 135153102).
135153100 divided by its reverse (1351531) gives a square (100 = 102).
The spelling of 135153100 in words is "one hundred thirty-five million, one hundred fifty-three thousand, one hundred".
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