Base | Representation |
---|---|
bin | 11001001101000001… |
… | …01011110001101111 |
3 | 1021220222222020000212 |
4 | 30212200223301233 |
5 | 210202414112030 |
6 | 10114400213035 |
7 | 656211431204 |
oct | 144640536157 |
9 | 37828866025 |
10 | 13531004015 |
11 | 5813998651 |
12 | 275760a17b |
13 | 13783c0a69 |
14 | 9250b1cab |
15 | 542d91595 |
hex | 32682bc6f |
13531004015 has 4 divisors (see below), whose sum is σ = 16237204824. Its totient is φ = 10824803208.
The previous prime is 13531003931. The next prime is 13531004051. The reversal of 13531004015 is 51040013531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13531004015 is a prime.
It is a super-2 number, since 2×135310040152 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1353100397 + ... + 1353100406.
It is an arithmetic number, because the mean of its divisors is an integer number (4059301206).
Almost surely, 213531004015 is an apocalyptic number.
13531004015 is a deficient number, since it is larger than the sum of its proper divisors (2706200809).
13531004015 is an equidigital number, since it uses as much as digits as its factorization.
13531004015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2706200808.
The product of its (nonzero) digits is 900, while the sum is 23.
Adding to 13531004015 its reverse (51040013531), we get a palindrome (64571017546).
The spelling of 13531004015 in words is "thirteen billion, five hundred thirty-one million, four thousand, fifteen".
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