Base | Representation |
---|---|
bin | 11001001101000010… |
… | …10000110000100101 |
3 | 1021221000020220211011 |
4 | 30212201100300211 |
5 | 210202433433433 |
6 | 10114403342221 |
7 | 656212631632 |
oct | 144641206045 |
9 | 37830226734 |
10 | 13531155493 |
11 | 5813a91439 |
12 | 2757681971 |
13 | 13784449ab |
14 | 925111189 |
15 | 542dc13cd |
hex | 326850c25 |
13531155493 has 2 divisors, whose sum is σ = 13531155494. Its totient is φ = 13531155492.
The previous prime is 13531155487. The next prime is 13531155499. The reversal of 13531155493 is 39455113531.
It is a balanced prime because it is at equal distance from previous prime (13531155487) and next prime (13531155499).
It can be written as a sum of positive squares in only one way, i.e., 8017053444 + 5514102049 = 89538^2 + 74257^2 .
It is an emirp because it is prime and its reverse (39455113531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13531155493 - 221 = 13529058341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13531155499) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765577746 + 6765577747.
It is an arithmetic number, because the mean of its divisors is an integer number (6765577747).
Almost surely, 213531155493 is an apocalyptic number.
It is an amenable number.
13531155493 is a deficient number, since it is larger than the sum of its proper divisors (1).
13531155493 is an equidigital number, since it uses as much as digits as its factorization.
13531155493 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 121500, while the sum is 40.
The spelling of 13531155493 in words is "thirteen billion, five hundred thirty-one million, one hundred fifty-five thousand, four hundred ninety-three".
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