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135312113300 = 225272136533253
BaseRepresentation
bin111111000000100111…
…0101111111010010100
3110221021010121120010212
41332001032233322110
54204104400111200
6142054520104552
712530105662100
oct1760116577224
9427233546125
10135312113300
1152427184511
1222283905158
13c9b55b2940
146798bb4900
1537be3bd035
hex1f813afe94

135312113300 has 216 divisors, whose sum is σ = 368517335256. Its totient is φ = 42745328640.

The previous prime is 135312113269. The next prime is 135312113317. The reversal of 135312113300 is 3311213531.

It can be written as a sum of positive squares in 12 ways, for example, as 32626474384 + 102685638916 = 180628^2 + 320446^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 41594474 + ... + 41597726.

Almost surely, 2135312113300 is an apocalyptic number.

135312113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 135312113300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (184258667628).

135312113300 is an abundant number, since it is smaller than the sum of its proper divisors (233205221956).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135312113300 is a wasteful number, since it uses less digits than its factorization.

135312113300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3947 (or 3933 counting only the distinct ones).

The product of its (nonzero) digits is 810, while the sum is 23.

Adding to 135312113300 its reverse (3311213531), we get a palindrome (138623326831).

The spelling of 135312113300 in words is "one hundred thirty-five billion, three hundred twelve million, one hundred thirteen thousand, three hundred".