Base | Representation |
---|---|
bin | 11110110001011101100111… |
… | …011100100111111110110100 |
3 | 122202012102100122220102121011 |
4 | 132301131213130213332310 |
5 | 120214404220201140200 |
6 | 1155502313332002004 |
7 | 40336011342665446 |
oct | 3661354734477664 |
9 | 582172318812534 |
10 | 135340450021300 |
11 | 3a13a62079a757 |
12 | 13219a76a60304 |
13 | 5a6971b833ba4 |
14 | 255c726d1a496 |
15 | 109a7b07055ba |
hex | 7b1767727fb4 |
135340450021300 has 36 divisors (see below), whose sum is σ = 303815975743980. Its totient is φ = 52269415179520.
The previous prime is 135340450021253. The next prime is 135340450021339. The reversal of 135340450021300 is 3120054043531.
It can be written as a sum of positive squares in 6 ways, for example, as 1184105243556 + 134156344777744 = 1088166^2 + 11582588^2 .
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 23334557449 + ... + 23334563248.
It is an arithmetic number, because the mean of its divisors is an integer number (8439332659555).
Almost surely, 2135340450021300 is an apocalyptic number.
135340450021300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
135340450021300 is an abundant number, since it is smaller than the sum of its proper divisors (168475525722680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135340450021300 is a wasteful number, since it uses less digits than its factorization.
135340450021300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46669120740 (or 46669120733 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
The spelling of 135340450021300 in words is "one hundred thirty-five trillion, three hundred forty billion, four hundred fifty million, twenty-one thousand, three hundred".
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