Base | Representation |
---|---|
bin | 11001001101011001… |
… | …11001001010001011 |
3 | 1021221012222211100101 |
4 | 30212230321022023 |
5 | 210204224021210 |
6 | 10114552550231 |
7 | 656250561214 |
oct | 144654711213 |
9 | 37835884311 |
10 | 13534204555 |
11 | 5815784223 |
12 | 27586b2377 |
13 | 1378c71781 |
14 | 9256a640b |
15 | 5432c4a3a |
hex | 326b3928b |
13534204555 has 8 divisors (see below), whose sum is σ = 16446628800. Its totient is φ = 10690308096.
The previous prime is 13534204513. The next prime is 13534204559. The reversal of 13534204555 is 55540243531.
13534204555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13534204555 - 221 = 13532107403 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13534204559) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17131510 + ... + 17132299.
It is an arithmetic number, because the mean of its divisors is an integer number (2055828600).
Almost surely, 213534204555 is an apocalyptic number.
13534204555 is a deficient number, since it is larger than the sum of its proper divisors (2912424245).
13534204555 is an equidigital number, since it uses as much as digits as its factorization.
13534204555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34263893.
The product of its (nonzero) digits is 180000, while the sum is 37.
It can be divided in two parts, 13534 and 204555, that added together give a square (218089 = 4672).
The spelling of 13534204555 in words is "thirteen billion, five hundred thirty-four million, two hundred four thousand, five hundred fifty-five".
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