Base | Representation |
---|---|
bin | 1100010011110100110000… |
… | …1001101010110101100110 |
3 | 1202220220110212200021022120 |
4 | 3010331030021222311212 |
5 | 3233223101201142440 |
6 | 44441433032210410 |
7 | 2564564652662205 |
oct | 304751411526546 |
9 | 52826425607276 |
10 | 13534719552870 |
11 | 434905137a13a |
12 | 1627152239a06 |
13 | 77241abb6ac9 |
14 | 34b1263d123c |
15 | 1871083eedd0 |
hex | c4f4c26ad66 |
13534719552870 has 128 divisors (see below), whose sum is σ = 32661999360000. Its totient is φ = 3589483422720.
The previous prime is 13534719552869. The next prime is 13534719552943. The reversal of 13534719552870 is 7825591743531.
13534719552870 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6637919311 + ... + 6637921349.
It is an arithmetic number, because the mean of its divisors is an integer number (255171870000).
Almost surely, 213534719552870 is an apocalyptic number.
13534719552870 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13534719552870 is an abundant number, since it is smaller than the sum of its proper divisors (19127279807130).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13534719552870 is a wasteful number, since it uses less digits than its factorization.
13534719552870 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3878.
The product of its (nonzero) digits is 31752000, while the sum is 60.
The spelling of 13534719552870 in words is "thirteen trillion, five hundred thirty-four billion, seven hundred nineteen million, five hundred fifty-two thousand, eight hundred seventy".
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